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## Re: please help with math problem

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X-2

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sqr(x+5)

multiply denominator by sqr(x+5) to get rid of the sqr, and whatever you do to the denominator, you gotta do to the numerator, so:

X-2 * sqr(x+5)

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sqr(x+5) * sqr(x+5)

the square root of somthing times itself equals that number (like square root of 2 * square root of 2 = 2, so you can solve the denominator,

X-2 * sqr(x+5)

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x+5

now ur looking for domain, which means what numbers can the x value be, while still making the equation a function,

so, what numbers don't make the denominator zero? the answer is: all real numbers, except for that number

you could have answered it without changing what the equation looks like, i just tried to simplify it.