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Nov 30 2006
By: AkiraXiju~ Wastelander 824 posts
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Physics problem...

7 replies 2 views Edited Nov 30, 2006
Can someone help me with this one...
I need to find the angle (theta) that when an object is launched from it, it will go the same distance vertically as horizontally. So if it went 100 feet up in the Y axis it also went 100 feet in the X axis. Thanks.
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Wastelander
Registered: 08/21/2005
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Re: Physics problem...

Nov 30, 2006
bump pwwwease?
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Gaming Beast
Registered: 09/03/2005
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Re: Physics problem...

Nov 30, 2006
I took IB physics last year, and it was so hard. I really don't remember that stuff, sorry!
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Fender Bender
Registered: 07/28/2004
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Re: Physics problem...

Nov 30, 2006
I did really think about it much just took a glance at your post, so I might be totally off, but did you try using Triganometry?  Sin, Cos, Tan?  That might help you.  Actually I think you would use tan^-1(opposite/adjacent).





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Wastelander
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Re: Physics problem...

Nov 30, 2006
Yea, that would yeild an angle of 63.4 degrees. However that is not the answer
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Fender Bender
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Re: Physics problem...

Nov 30, 2006
Do you know the vertical distance?





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Wastelander
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Re: Physics problem...

Nov 30, 2006
Well, not exactly but it equals the horizontal distance. So far all I could come up with is...

ViSin(theta)(time) - 1/2at^2 = ViCos(theta) (2time)
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Fender Bender
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Re: Physics problem...

Nov 30, 2006
Not sure if this will help, I don't know the givens.  But I have a formula Vf^2 = Vi^2 + 2a(delta)X
X is displacement as far as our teacher has told us, don't know if you use something differen.t





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